计算机科学导论习题答案(Introduction to computer science, exercises, answers).doc
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1、计算机科学导论习题答案(Introduction to computer science, exercises, answers)Introduction to computer science, exercises, answersChapter 1I. multiple-choice questions1-5, A, D, B, D, DTwo. Fill in the blanks1 fast processing, large storage capacity, high reliability and high accuracy2 tubes, transistors, small
2、and medium scale integrated circuits, very large scale integrated circuits3 not having their own ideas, no good intuition and imagination, speed and memory capacity is far from meeting the actual needsThree. Questions and answers1 the development of computers is divided into five generations:The fir
3、st generation: components using electronic tubes, large size, slow speed, the machine provides the original instructions to prepare procedures.The second generation: components using transistors and printed circuit, the volume has been reduced, the function continues to increase, you can run assembl
4、y language and high-level language, a large number of applications appear.The third generation: using small and medium scale integrated circuits, the system management program is raised to the operating system.The fourth generation: Based on large-scale integrated circuit and very large scale integr
5、ated circuit, more powerful, smaller size.The fifth generation: artificial intelligence computer.21) scientific engineering calculation, including numerical calculation, engineering design and scientific calculation, computer aided design, weather forecasting, agriculture and animal husbandry.2) pro
6、cess control, including: automatic control, monitoring, instrumentation.3) information processing, including information management, enterprise management, information retrieval, material handling and transaction processing.Second chaptersI. multiple-choice questionsThe C A C D D D B A C AThe B A B
7、B C B A B B CThe C B C B A A D D D DTwo. Fill in the blanks1 arithmetic operations, logical operations2 instructions3 disk, tape, CD4 fixed point floating point5 3755, 30086 input devices7 48 19 input10 address11 bitmap representation, vector notation12 813 baseline, cycle, amplitude14 sampling freq
8、uency and quantization accuracyThree. Questions and answers1 with binary digit symbol representation is simple, as long as the choice of two components can be simply expressed on digital numbers 0 and 1, so the low price, easy to implement and use; simple operation rules, so as to realize the logica
9、l structure of the simple computer operation; to realize the logic operation, you can use 1 said the true value, 0 false value, its operation is a binary operation, fully consistent with the binary.2: integer except 2 remainder method; decimal rounding method: take 23 because of the digital binary n
10、umber representation is relatively long, not for writing and reading, so consider using both less bits without losing the binary number system to represent the characteristics of. So you can convert binary numbers into octal and sixteen hexadecimal numbers.4 the position of the decimal point of an i
11、nteger is fixed, while the decimal position of the real number floats according to the magnitude of the value.5 location codes for Chinese characters.6 when the fixed point is expressed, the position of the decimal point is fixed. When the floating point is expressed, the decimal point position is n
12、ot fixed.These two forms are used to represent integers, fixed points, decimals, and real numbers.Four. Comprehensive questions1Location codemachine codeMachine code (16 hexadecimal)in5448214208D6H D0Hcountry2590185250B9H FAHto5158211218D3H DAHTwo00110010 (32H)00110010 (32H)32HZero00110000 (30H)0011
13、0000 (30H)30HZero00110000 (30H)00110000 (30H)30HOne00110001 (31H)00110001 (31H)31Hyear3674196234C4H EAHjust5393213253D5H FDHtype4229202189CAH BDHplus2851188211BCH D3Henter4075200235C8H EBHThe3343193203C1H CBHW01010111 (57H)01010111 (57H)57HT01010100 (54H)01010100 (54H)54HO01001111 (4FH)01001111 (4FH
14、)4FH2 convert to binary: 111001110.100010110000Or as shown in table 2-1, in BCD Code: 010001100010.0101010000113Location code (10 hex)Location code (16 hex)GB code (10 hex)GB code (16 hex)Machine code (10 m)Machine code (16 m)meter28381CH 26H60703CH 46H188198BC C6count43672BH 43H75994BH 63H203227CB
15、E3machine27901BH 5AH591223BH 7AH187250BB FA4 3300030Third chaptersI. multiple-choice questionsThe B B C D C C B C B C11 CTwo. Fill in the blanks1 simplification of logic function2 or3 logical circuits4 AB+AC5 refers to the commands that can be sent to the computer, which can be understood by the com
16、puter, so that the computer can perform one of the most basic operations. Operational information, data information6 take instructions, analyze instructions, execute instructions, and automatically take down an instruction7 input and output8 operation code, address codeThree. Questions and answers1
17、1) the number of computer storage is discrete; 2) the length of the computer storage unit is fixed; 3) in the computer, the number of positive and negative numbers are represented by numbers; 0 is positive, and 1 is negative.2 the complement notation greatly simplifies the processing of operations a
18、nd reduces the number of generations by adding the inverse number of the number, making subtraction into addition.3 provide tools for generating complement complement.4 take instructions, analyze instructions, execute instructions, and automatically take down an instruction.5 logical multiplication,
19、 logical addition, logical non operation.Logical multiply: when the inputs are true, the result is trueLogical addition: when one of the inputs is true, the result is trueLogical: when the input is false, the result is true61) arithmetic class. 2) logical operations class. 3) transport class. 4) pro
20、gram control class. 5) input / output class. 6) other classes.7A program is an ordered set of instructions designed to complete a processing task.Programming is the method by which tasks can be effectively converted into programs.Before the program is executed, the address of a start command must be
21、 provided and stored in the instruction counter. The controller according to this address out of the first instruction, and the instruction itself is stored in the controller instruction register; the instruction decoder controller to the instruction operation code analysis, understand the instructi
22、ons on what to do; carry out specific operations according to the results of the analysis, to complete the task that refers to the expression, and to fetch the next instruction to do prepare, namely instruction counter plus 1. Thus, the program is executed under the control of the controller, in coo
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